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How do you solve #-5(2x-4)=60#?

Answer 1

Eva Adamson

#x=-4#

#"divide both sides by "-5#

#cancel(-5)/cancel(-5)(2x-4)=60/(-5)#

#2x-4=-12#

#"add 4 to both sides"#

#2xcancel(-4)cancel(+4)=-12+4#

#2x=-8#

#"divide both sides by 2"#

#x=(-8)/2=-4#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#-5(-8-4)=-5xx-12=60#

#x=-4" is the solution"#

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Answer 2

Avery Alexander

To solve -5(2x-4)=60, first distribute the -5 across the parentheses to get -10x + 20 = 60. Then, subtract 20 from both sides to isolate -10x, resulting in -10x = 40. Finally, divide both sides by -10 to solve for x, giving x = -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.