How do you solve #5(2b+7)+b< b11#?
First, expand the term in parenthesis:
Next, combine like terms:
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To solve the inequality 5(2b+7)+b < b11, follow these steps:

Distribute the 5 across the parentheses: 10b  35 + b < b  11

Combine like terms: 9b  35 < b  11

Add b to both sides to isolate terms with b: 9b + b  35 < b + b  11 8b  35 < 11

Add 35 to both sides to isolate 8b: 8b  35 + 35 < 11 + 35 8b < 24

Divide both sides by 8. Remember to reverse the inequality since you're dividing by a negative number: (8b) / 8 > 24 / 8 b > 3
So, the solution to the inequality is b > 3.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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