How do you solve #-5(-2-3k)=-65# using the distributive property?

Answer 1

#k=-5#

#"multiply the terms in the bracket by - 5"#
#rArr10+15k=-65larrcolor(blue)" distributive property"#
#"isolate 15k on the left by subtracting 10 from both sides"#
#cancel(10)cancel(-10)+15k=-65-10#
#rArr15k=-75#
#"divide both sides by 15"#
#(cancel(15) k)/cancel(15)=(-75)/15#
#rArrk=-5#
#color(blue)"As a check"#

#Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=-5(-2+15)=-5xx13=-65=" right"#
#rArrk=-5" is the solution"#
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Answer 2

To solve the equation -5(-2-3k)=-65 using the distributive property:

  1. Distribute -5 across (-2-3k): -5 * -2 = 10 and -5 * -3k = 15k.
  2. Rewrite the equation with the distributed terms: 10 + 15k = -65.
  3. Subtract 10 from both sides: 15k = -75.
  4. Divide both sides by 15: k = -5.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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