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How do you solve #(4z + 2) ( 1- z ) = 0#?

Answer 1

Savannah Anderson

See a solution process below:

To solve this and find the roots of the equation equate each term on the left to #0# and solve for #z#:

Solution 1:

#4z + 2 = 0#

#4z + 2 - color(red)(2) = 0 - color(red)(2)#

#4z + 0 = -2#

#4z = -2#

#(4z)/color(red)(4) = -2/color(red)(4)#

#(color(red)(cancel(color(black)(4)))z)/cancel(color(red)(4)) = -1/2#

#z = -1/2#

Solution 2:

#1 - z = 0#

#1 - z + color(red)(z) = 0 + color(red)(z)#

#1 - 0 = z#

#1 = z#

#z = 1#

The Solution Set Is: #z = {-1/2, 1}#

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Answer 2

Eva Abramson

To solve the equation (4z + 2)(1 - z) = 0, you first expand the expression to get 4z - 4z^2 + 2 - 2z. Then, set each factor equal to zero and solve for z. So, 4z - 4z^2 + 2 - 2z = 0 becomes 4z - 4z^2 + 2 - 2z = 0. Then, simplify the equation to get 4z - 4z^2 + 2 - 2z = 0. Simplify it further to obtain -4z^2 + 2z + 2 = 0. Finally, solve for z using factoring or the quadratic formula.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.