How do you solve #4x^24x=15#?
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To solve the equation 4x^2  4x = 15, you can follow these steps:

Move all terms to one side of the equation to set it equal to zero: 4x^2  4x  15 = 0.

Factor the quadratic equation or use the quadratic formula to find the roots.

If factoring is possible, factor the quadratic expression. If not, apply the quadratic formula.

Apply the quadratic formula, which states that for the quadratic equation ax^2 + bx + c = 0, the solutions are given by x = (b ± √(b^2  4ac)) / (2a).

Substitute the values of a, b, and c from the given equation into the quadratic formula.

Solve for x by performing the necessary arithmetic operations.

Once you have found the values of x, check your solutions by substituting them back into the original equation to ensure they satisfy the equation.
By following these steps, you can find the solutions to the equation 4x^2  4x = 15.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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