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How do you solve #4x - 2 = 2x + 8#?

Answer 1

Ethan Adkins

#x=5#

#color(blue)(4x)color(red)(-2)=color(blue)(2x)+color(red)8#

Move similar terms to one side:

#4x-2x=8+2#

#2x=10#

Divide both sides by #2#:

#x=5#

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Answer 2

Eli Assouline

#x = 5#

# 4x - 2 = 2x + 8 #

We eleminate 2x on the right by substracting 2x from each side. Equivalently, we can add -2x to both sides. #4x - 2 color(red)( -2x) = 2x color(red)(-2x) +8 #

Simplify # 2x -2 = 8 #

Add 2 to each side. # 2x-2 color(red)(+2 )= 8 color(red)(+2) #

#2x = 10 #

Multiply each side by 1/2 #2x color(red)(xx(1/2)) = 10 color(red)(xx 1/2#

#x =5#

Check !

# 4x - 2 = 2x + 8 # substitute x=5 into equation

#4(5) - 2 = 2(5) +8# #20 - 2= 10 +8 # #18 = 18#

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Answer 3

Abigail Allen

To solve the equation 4x - 2 = 2x + 8, first, you need to get all the x terms on one side of the equation and the constants on the other side.

Start by subtracting 2x from both sides: 4x - 2x - 2 = 2x - 2x + 8

This simplifies to: 2x - 2 = 8

Then, add 2 to both sides: 2x - 2 + 2 = 8 + 2

This simplifies to: 2x = 10

Finally, divide both sides by 2: 2x/2 = 10/2

This simplifies to: x = 5

So, the solution to the equation is x = 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.