How do you solve -4x-13 or x+27?

Question

How do you solve -4x-1>3 or x+2>7?

Eva Abramson · Accepted Answer

#x < -1 or x > 5#
#color(white)("XXX")#OR
#abs(x-2) > 3# Part 1 #color(white)("XXX")-4x-1 > 3# add #4x-3# to both sides #color(white)("XXX")-4 > 4x# divide by #4# #color(white)("XXX")-1 > x# or, equivalently #color(white)("XXX")x < -1# Part 2 #color(white)("XXX")x+2 > 7# subtract #2# from both sides #color(white)("XXX")x > 5# Note that for #x < -1# or #x > 5# #color(white)("XXX")x# must be further that #2# the midpoint between #(-1)# and #(5)# (i.e. from #3#) So #color(white)("XXX")abs(x-2) > 3#

Avery Alexander · Answer

undefined To solve the inequality -4x - 1 > 3 or x + 2 > 7, we can treat each inequality separately and then find the intersection of their solution sets. For the first inequality, -4x - 1 > 3: Add 1 to both sides: -4x > 4 Divide both sides by -4 (note that when dividing or multiplying an inequality by a negative number, the direction of the inequality sign flips): x < -1 For the second inequality, x + 2 > 7: Subtract 2 from both sides: x > 5 So, the solution to the compound inequality is -1 < x < 5.

How do you solve -4x-1&gt;3 or x+2&gt;7?

How do you solve -4x-1>3 or x+2>7?