How do you solve #4abs(r+7)+3=59#?

Answer 1

#r=7# or #r=-21#

As #4|r+7|+3=59#
#4|r+7|=59-3=56#
or #|r+7|=56/4=14#
Now #|r+7|# stands for modulus or absolute value of #r+7#. And hence as it is equal to #14#,
we either have #r+7=14# i.e. #r=14-7=7#
or #r+7=-14# i.e, #r=-14-7=-21#
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Answer 2

To solve the equation 4|r + 7| + 3 = 59, first subtract 3 from both sides to isolate the absolute value term: 4|r + 7| = 56. Then, divide both sides by 4: |r + 7| = 14. Now, since the absolute value of a number can be either positive or negative, you have two cases to consider: r + 7 = 14 and r + 7 = -14. Solve each equation separately to find the possible values of r. For the first case, subtract 7 from both sides to get r = 7. For the second case, subtract 7 from both sides to get r = -21. Therefore, the solutions to the equation are r = 7 and r = -21.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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