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How do you solve #48/8 =abs(x^3)#?

Answer 1

Avery Alexander

#x=pmroot(3)(6)#

If #x>=0# we get #x^3=6#

If #x<0# we get #6=(-x)^3#

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Answer 2

Savannah Anderson

First, divide 48 by 8 to get 6. Then, rewrite the equation as 6 = abs(x^3). Finally, take the cube root of both sides to solve for x: x = ±∛6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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