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How do you solve #43(3x+1)-(x-1)=6(x+10)#?

Answer 1

See explanation

Use the distributive property to get #129x+43-x+1=6x+60#. Combine like terms to get #128x +44=6x+60#. Subtract 44 from each side to get #128x=6x+16#. Subtract 6x from each side to get #122x=16#. Divide each side by 122 to get #x=8/61#.

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Answer 2

Isaiah Anthony

To solve the equation 43(3x + 1) - (x - 1) = 6(x + 10), follow these steps:

Distribute the terms inside the parentheses: 43(3x + 1) = 129x + 43 -(x - 1) = -x + 1 6(x + 10) = 6x + 60
Substitute the distributed terms back into the equation: 129x + 43 - (-x + 1) = 6x + 60
Simplify the equation by combining like terms: 129x + 43 + x - 1 = 6x + 60 130x + 42 = 6x + 60
Move the variable terms to one side of the equation and the constants to the other side: 130x - 6x = 60 - 42 124x = 18
Divide both sides by the coefficient of the variable: x = 18 / 124
Simplify the fraction if possible: x = 9 / 62

Therefore, the solution to the equation 43(3x + 1) - (x - 1) = 6(x + 10) is x = 9/62.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.