How do you solve #4(y-2/4)=9(y+1/3) #?

Question

How do you solve #4(y-2/4)=9(y+1/3)   #?

Eli Assouline · Accepted Answer

#y=-1#

#4(y-2/4)=9(y+1/3)#

According to BEDMAS, work on the brackets first. Reduce #2/4# to #1/2#.

#4(y-1/2)=9(y+1/3)#

Ensure that the terms in brackets share the same denominator.

#4((2y)/2-1/2)=9((3y)/3+1/3)#

Take away the terms in brackets.

#4((2y-1)/2)=9((3y+1)/3)#

By canceling, the fractions are reduced.

#color(red)cancelcolor(black)4^2((2y-1)/color(red)cancelcolor(black)2)=color(blue)cancelcolor(black)9^3((3y+1)/color(blue)cancelcolor(black)3)#

Write the equation again.

#2(2y-1)=3(3y+1)#

Do a multiplication.

#4y-2=9y+3#

Isolate for #y# by bringing all terms with #y# to the left and all without to the right.

#4y-9y=3+2#

Resolve.

#-5y=5#

#y=-1#

Genesis Allen · Answer

undefined To solve $4(y-\frac{2}{4})=9(y+\frac{1}{3})$:

1. Distribute the constants and simplify each side of the equation.
2. Combine like terms.
3. Solve for the variable $y$.

Isaiah Anthony · Answer

undefined To solve the equation $4(y - \frac{2}{4}) = 9(y + \frac{1}{3})$, follow these steps:

Expand both sides of the equation:
$$4y - 1 = 9y + 3$$

Move the variable terms to one side and constants to the other side:
$$4y - 9y = 3 + 1$$
$$4y - 9y = 4$$

Combine like terms:
$$-5y = 4$$

Divide both sides by -5:
$$y = \frac{4}{-5}$$

Simplify:
$$y = -\frac{4}{5}$$

So, the solution to the equation is $y = -\frac{4}{5}$.