How do you solve #4/x+7=6/x#?

Answer 1

The solution is #x=2/7#.

Multiply everything by #x# to get rid of the #x# in the denominator:
#4/x+7=6/x#
#4/xcolor(blue)(*x)+7color(blue)(*x)=6/xcolor(blue)(*x)#
#4/color(red)cancelcolor(black)xcolor(blue)(*color(red)cancelcolor(blue)x)+7color(blue)(*x)=6/color(red)cancelcolor(black)xcolor(blue)(*color(red)cancelcolor(blue)x)#
#4+7color(blue)(*x)=6#
#4+7x=6#
#4+7xcolor(blue)-color(blue)4=6color(blue)-color(blue)4#
#color(red)cancelcolor(black)4+7xcolor(red)cancelcolor(black)(color(blue)-color(blue)4)=6color(blue)-color(blue)4#
#7x=6color(blue)-color(blue)4#
#7x=2#
#color(blue)(color(black)(7x)/7)=color(blue)(color(black)2/7)#
#color(blue)(color(black)(color(red)cancelcolor(black)7x)/color(red)cancelcolor(blue)7)=color(blue)(color(black)2/7)#
#x=color(blue)(color(black)2/7)#

That's the solution. Hope this helped!

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Answer 2

#2/7#

#4/x +7=6/x#
#rArr 4/x - 6/x=-7#
#rArr (4-6)/x = -7#
#rArr -2/x =-7#
#rArr x=2/7#

Hope this helps :)

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Answer 3

To solve the equation 4/x + 7 = 6/x, you can start by getting rid of the denominators by multiplying both sides of the equation by x. This gives you 4 + 7x = 6. Next, you can isolate the variable by subtracting 4 from both sides, resulting in 7x = 2. Finally, divide both sides of the equation by 7 to solve for x, giving you x = 2/7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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