How do you solve #4(x + 6) = 32#?

Answer 1

#x=2#

Given that x and 6 are both multiplied by 4, we can do the following by multiplying both sides by 1/4:

#(4(x+6))/4=(32)/4#
#x+6=8#

All that's left to do is deduct 6 from each side! :D

#x=2#
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Answer 2

To solve 4(x + 6) = 32, first distribute the 4 to both terms inside the parentheses: 4x + 24 = 32 Then, subtract 24 from both sides: 4x = 8 Finally, divide both sides by 4: x = 2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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