How do you solve #4/(x+2 )*( x^2-4)/(4x-8)#?
The expression will equal
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To solve the expression 4/(x+2) * (x^2-4)/(4x-8), we can simplify it by canceling out common factors.
First, let's factor the numerator and denominator of each fraction:
- The numerator of the first fraction, x^2-4, can be factored as (x+2)(x-2).
- The denominator of the second fraction, 4x-8, can be factored as 4(x-2).
Now, we can cancel out the common factors:
- The (x+2) in the numerator of the first fraction cancels out with the (x+2) in the denominator of the second fraction.
- The (x-2) in the numerator of the second fraction cancels out with the (x-2) in the denominator of the first fraction.
After canceling out the common factors, we are left with: 4/4
This simplifies to: 1
Therefore, the expression 4/(x+2) * (x^2-4)/(4x-8) simplifies to 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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