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How do you solve #4(x-2)=5#?

Answer 1

Genesis Allen

#x = 13/4#

Divide both sides by 4 to get

#x-2 = 5/4#

Add #2# to both sides to get

#x = 5/4 +2#

Calculate and get

#x = 13/4#

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Answer 2

Julia Adams

See a solution process below:

Step 1) Divide each side of the equation by #color(red)(4)# to eliminate the need for parenthesis while keeping the equation balanced:

#(4(x - 2))/color(red)(4) = 5/color(red)(4)#

#(color(red)(cancel(color(black)(4)))(x - 2))/cancel(color(red)(4)) = 5/4#

#x - 2 = 5/4#

Step 2) Add #color(red)(2)# to each side of the equation to solve for #x# while keeping the equation balanced:

#x - 2 + color(red)(2) = 5/4 + color(red)(2)#

#x - 0 = 5/4 + (4/4 xx color(red)(2))#

#x = 5/4 + 8/4#

#x = 13/4#

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Answer 3

Isaiah Anthony

To solve 4(x-2)=5, first distribute 4 to x and -2, then isolate x by moving constants to one side and variables to the other side.

Step 1: Distribute 4: 4x - 8 = 5 Step 2: Add 8 to both sides: 4x = 13 Step 3: Divide both sides by 4: x = 13/4 or x = 3.25

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.