# How do you solve # 4 /(x+1 )+ 3 /(x - 4) = 2 /( x +1)#?

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Our plan is to get rid of quotients.

Now take 4 out of the equation on both sides.

Apply the distributive property now, and let's stop using quotients.

From both sides of this equation, subtract 3.

This equation's two sides should be divided by 5.

We can verify our response.

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To solve the equation 4/(x+1) + 3/(x-4) = 2/(x+1), we can follow these steps:

- Multiply the entire equation by the common denominator, which is (x+1)(x-4). This will eliminate the denominators.

(x+1)(x-4) * [4/(x+1) + 3/(x-4)] = (x+1)(x-4) * 2/(x+1)

- Simplify the equation by distributing and canceling out common factors:

4(x-4) + 3(x+1) = 2(x-4)

- Expand and simplify the equation:

4x - 16 + 3x + 3 = 2x - 8

7x - 13 = 2x - 8

- Move all the variables to one side and the constants to the other side:

7x - 2x = -8 + 13

5x = 5

- Solve for x by dividing both sides of the equation by 5:

x = 1

Therefore, the solution to the equation 4/(x+1) + 3/(x-4) = 2/(x+1) is x = 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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