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How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

Answer 1

#c=4#

Expand all the terms first #4c+4+2c+3c-3=37# Then shift all the numbers to the left #4c+2c+3c=37+3-4# #9c=36# Then divide both sides by 9 #(9c)/9=36/9# #c=4#

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Answer 2

Avery Alexander

To solve the equation 4(c + 1) + 2c + 3(c - 1) = 37:

Step 1: Distribute the terms inside the parentheses: 4c + 4 + 2c + 3c - 3 = 37

Step 2: Combine like terms: 9c + 1 = 37

Step 3: Subtract 1 from both sides to isolate the variable term: 9c = 36

Step 4: Divide both sides by 9 to solve for c: c = 4

Therefore, the solution to the equation is c = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.