How do you solve #4=(5z+2)/3#?

Answer 1

#color(green)(z = 2")#

#color(indigo)("Multiply 3 on both sides to get rid of the denominator:")#
#4xx3=(5z+2)/cancel3##xxcancel3#
#color(hotpink)("Subtract 2 on both sides to get the constant by itself:")#
#12 = 5z+2# #-2 color(white)(aaaa) -2#
#10=5z#
#color(green)("Divide both sides by 5 to find z:")# #10/5=(cancel5z)/cancel5#
#2=z#
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Answer 2

To solve for ( z ) in the equation ( 4 = \frac{5z + 2}{3} ), you can follow these steps:

  1. Multiply both sides of the equation by 3 to eliminate the fraction: ( 4 \times 3 = \frac{5z + 2}{3} \times 3 ).
  2. Simplify both sides: ( 12 = 5z + 2 ).
  3. Subtract 2 from both sides: ( 12 - 2 = 5z + 2 - 2 ).
  4. Simplify: ( 10 = 5z ).
  5. Divide both sides by 5 to isolate ( z ): ( \frac{10}{5} = \frac{5z}{5} ).
  6. Simplify: ( 2 = z ).

Therefore, the solution to the equation is ( z = 2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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