How do you solve #4=4(k+3)# using the distributive property?

Answer 1

k = - 2

The terms inside the bracket are multiplied by four according to the distributive property.

#rArr4=color(red)(4)(k+3)=4k+12#

We now need to figure out 4k + 12 = 4.

From both sides of the equation, deduct 12.

#rArr4k+12cancel(-12)=4-12#

In other words, 4k = - 8.

divide each side by four.

#rArr(cancel(4)^1 k)/cancel(4)^1=cancel(-8)^(-2)/cancel(4)^1rArrk=-2#
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Answer 2

To solve 4 = 4(k + 3) using the distributive property, distribute 4 across the parentheses. This yields: 4 = 4k + 12. Then, isolate the variable term by subtracting 12 from both sides. This gives: 4 - 12 = 4k. Simplify to get: -8 = 4k. Finally, divide both sides by 4 to solve for k, resulting in k = -2.

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Answer 3

To solve the equation 4 = 4(k + 3) using the distributive property, follow these steps:

  1. Distribute the 4 on the right side of the equation: 4(k + 3) = 4k + 12

  2. Now the equation becomes: 4 = 4k + 12

  3. Subtract 12 from both sides of the equation: 4 - 12 = 4k -8 = 4k

  4. Divide both sides by 4 to solve for k: -8 / 4 = k -2 = k

Therefore, the solution to the equation is k = -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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