How do you simplify #4 4/5 + 3 1/3#?

Answer 1

#8 2/15#

Work with the whole numbers first, and then deal with the fractions,

#color(blue)(4) 4/5 + color(blue)(3) 1/3#
#=color(blue)(7) +4/5+1/3" "larr# the #LCM = 15#
Make equivalent fractions with #15# in each denominator
#=7 + (4/5 xx 3/3) + (1/3 xx5/5)#
#=7 +12/15 +5/15#
#= 7 (12+5)/15#
#=7 17/15" "larr " change " 17/15 # into a mixed number
#=7 +1 2/15#
#=8 2/15#
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Answer 2

To simplify (4 \frac{4}{5} + 3 \frac{1}{3}), we first convert the mixed numbers to improper fractions.

(4 \frac{4}{5}) as an improper fraction is (\frac{4 \times 5}{5} + 4 = \frac{20}{5} + 4 = \frac{20 + 5}{5} = \frac{25}{5}).

(3 \frac{1}{3}) as an improper fraction is (\frac{3 \times 3}{3} + 1 = \frac{9}{3} + 1 = \frac{9 + 3}{3} = \frac{12}{3}).

Now, we add the fractions: (\frac{25}{5} + \frac{12}{3} = \frac{25 \times 3}{5 \times 3} + \frac{12 \times 5}{3 \times 5} = \frac{75}{15} + \frac{60}{15}).

Adding the fractions, we get (\frac{75 + 60}{15} = \frac{135}{15}).

Now, we simplify the fraction: (\frac{135}{15} = \frac{9 \times 15}{15} = 9).

So, (4 \frac{4}{5} + 3 \frac{1}{3} = 9).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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