How do you solve #-4(3x+2)=16#?

Answer 1

See a solution process below:

First, divide each side of the equation by #color(red)(-4)# to eliminate the need for parenthesis while keeping the equation balanced:
#(-4(3x + 2))/color(red)(-4) = 16/color(red)(-4)#
#(color(red)(cancel(color(black)(-4)))(3x + 2))/cancel(color(red)(-4)) = -4#
#3x + 2 = -4#
Next, subtract #color(red)(2)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#3x + 2 - color(red)(2) = -4 - color(red)(2)#
#3x + 0 = -6#
#3x = -6#
Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:
#(3x)/color(red)(3) = -6/color(red)(3)#
#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = -2#
#x = -2#
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Answer 2

#x=-2#

#"distribute the bracket"#
#-12x-8=16#
#"add 8 to both sides"#
#-12x=16+8=24#
#"divide both sides by "-12#
#(cancel(-12) x)/cancel(-12)=24/(-12)rArrx=-2#
#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#-4(-6+2)=-4xx-4=16#
#x=-2" is the solution"#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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