How do you solve #4(3-y)=6-2(1-3y)#?

Answer 1

Eva Adamson

#0.8#

#12-4y = 6- 2 + 6y#

#12-4y= 4+6y #

#12-4=6y + 4y#

#8 = 10y#

#y= 8/10#

#y = 0.8#

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Answer 2

Eli Assouline

To solve 4(3-y) = 6 - 2(1-3y), first distribute the terms:

4(3-y) = 12 - 4y 6 - 2(1-3y) = 6 - 2 + 6y = 4 + 6y

Now, equate the two expressions:

12 - 4y = 4 + 6y

Rearrange terms:

12 - 4 = 6y + 4y

Combine like terms:

8 = 10y

Divide both sides by 10:

8/10 = y

Simplify:

4/5 = y

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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