How do you solve #3x+9=-x+1#?

Answer 1

#x=-2#

Compile the terms in x on the left side and the numerical values on the right side of the equation.

To both sides, add x.

#3x+x+9=cancel(-x)cancel(+x)+1#
#rArr4x+9=1#

Deduct 9 from each side.

#4xcancel(+9)cancel(-9)=1-9#
#rArr4x=-8#

Divide both sides by 4 to find x.

#(cancel(4) x)/cancel(4)=(-8)/4#
#rArrx=-2" is the solution"#
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Answer 2

To solve the equation 3x + 9 = -x + 1, first, add x to both sides to get 4x + 9 = 1. Then, subtract 9 from both sides to get 4x = -8. Finally, divide both sides by 4 to isolate x, which gives x = -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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