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How do you solve #3x+82=x+2#?

Answer 1

Eva Abramson

#x=-40#

Subtract 82

#3x=x-80#

Subtract #x#

#2x=-80#

Divide by 2

#x=-40#

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Answer 2

Eva Abramson

#x=-40#

Let's see if we get our constants on the right and variables on the left. We can start by subtracting #x# from both sides to get

#2x+82=2#

Next, let's get the #82# on the right side by subtracting it from both sides.

#2x=-80#

Lastly, we divide both sides by #2# to get

#x=-40#

Hope this helps!

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Answer 3

Eli Assouline

To solve the equation 3x + 82 = x + 2, you first need to isolate the variable x. Subtract x from both sides of the equation, and then subtract 82 from both sides. This will leave you with 2x = -80. Finally, divide both sides by 2 to solve for x. You'll find that x = -40.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.