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How do you solve #3x + 5- 6( x + 1) = 4x + 5#?

Answer 1

Eva Adamson

#-6/7#

Step 1: Determine the value of the equation's parenthesis and brackets "( )".

#3x+5-6(x+1)=4x+5#

Turns into:

#3x+5-6x-6=4x+5#

Step 2) Put the variables (in this case, #x#) on one side of the equal sign and the real numbers on the other side.

#3x-6x-4x=5+6-5# (putting the variable on the left side of the equal sign is preferable)

Step 3: Resolve:

#-7x=6#

#x=-6/7#

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Answer 2

Kennedy Adams

To solve the equation 3x + 5 - 6(x + 1) = 4x + 5, first distribute the -6 across (x + 1) to get: 3x + 5 - 6x - 6 = 4x + 5. Then combine like terms to simplify: 3x + 5 - 6x - 6 = 4x + 5 becomes -3x - 1 = 4x + 5. Next, move the variables to one side by adding 3x to both sides: -1 = 7x + 5. Then, move the constant to the other side by subtracting 5 from both sides: -6 = 7x. Finally, divide by 7 to solve for x: x = -6/7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.