How do you solve #3x/4 = 6/7#?

Answer 1

#x = 6/7# or perhaps #(x =8/7)??#

The format of the question is strange

The question format is odd because mixed numbers are not typically used in algebra. (possibly a typo)

#3x/4 = 6/7#

If this is the correct fraction, we will switch to an incorrect fraction first:

#(4xx3+x)/4 = 6/7 " "rArr" " (12x)/4 = 6/7#
Cross multiplying gives: #84x = 24#
#x = 24/84 = 2/7# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ The question may have been meant as:
#(3x)/4 = 6/7#

When you cross multiply, you get

#21x = 24#
#x = 24/21 = 8/7#
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Answer 2

To solve the equation 3x/4 = 6/7, you can cross multiply to isolate x, then divide by the coefficient of x. The steps are as follows:

  1. Multiply both sides of the equation by 4 to eliminate the fraction: 4 * (3x/4) = 4 * (6/7).
  2. Simplify: 3x = 24/7.
  3. Divide both sides by 3 to isolate x: (3x)/3 = (24/7)/3.
  4. Simplify: x = 8/7.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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