How do you solve #-3x^2+5x=-2#?
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To solve the equation ( -3x^2 + 5x = -2 ), you can follow these steps:
- Rewrite the equation in standard form: ( -3x^2 + 5x + 2 = 0 ).
- Use the quadratic formula: ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ), where ( a = -3 ), ( b = 5 ), and ( c = 2 ).
- Substitute the values of ( a ), ( b ), and ( c ) into the formula and solve for ( x ).
After solving, you'll get two solutions for ( x ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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