How do you solve #-3x^2+5x=-2#?

Answer 1

#x=-1/3" or "x=2#

#"express in standard form "color(white)(x)ax^2+bx+c=0#
#"add 2 to both sides"#
#rArr-3x^2+5x+2=0#
#"multiply through by "-1#
#rArr3x^2-5x-2=0#
#"using the a-c method to factor"#
#"the factors of the product "3xx-2=-6#
#"which sum to - 5 are - 6 and + 1"#
#"split the middle term using these factors"#
#3x^2-6x+x-2=0larrcolor(blue)"factor by grouping"#
#color(red)(3x)(x-2)color(red)(+1)(x-2)=0#
#"take out the "color(blue)"common factor "(x-2)#
#rArr(x-2)(color(red)(3x+1))=0#
#"equate each factor to zero and solve for x"#
#3x+1=0rArrx=-1/3#
#x-2=0rArrx=2#
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Answer 2

To solve the equation ( -3x^2 + 5x = -2 ), you can follow these steps:

  1. Rewrite the equation in standard form: ( -3x^2 + 5x + 2 = 0 ).
  2. Use the quadratic formula: ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ), where ( a = -3 ), ( b = 5 ), and ( c = 2 ).
  3. Substitute the values of ( a ), ( b ), and ( c ) into the formula and solve for ( x ).

After solving, you'll get two solutions for ( x ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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