How do you solve #3x + 2< 5( x - 4)#?

Answer 1

#x > 11#

To just solve the equation for x, just do:

First, Distribute the #5(x-4)# #5x-20#

Second, from #3x+2 < 5x-20#, add 20 to the other side of the '<' and then subtract 3x to the other side where -20 was. Therefore, you would have: #22 < 2x#.

Finally, simply divide 2 on each side of the equation and you would get: #11 < x# or #x > 11#.

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Answer 2

Isaiah Anthony

To solve the inequality 3x + 2 < 5(x - 4), follow these steps:

Distribute the 5 on the right side: 5(x - 4) = 5x - 20.
Combine like terms: 3x + 2 < 5x - 20.
Subtract 3x from both sides: 2 < 2x - 20.
Add 20 to both sides: 22 < 2x.
Divide both sides by 2: 11 < x.

So, the solution to the inequality is x > 11.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #3x + 2&lt; 5( x - 4)#?

How do you solve #3x + 2< 5( x - 4)#?