How do you solve #3x^2=12x#?

Answer 1

#x=0" or "x=4#

#"rearrange into "color(blue)"standard form"#
#rArr3x^2-12x=0larrcolor(blue)"in standard form"#
#"take out a "color(blue)"common factor "3x#
#rArr3x(x-4)=0#
#"equate each factor to zero and solve for x"#
#3x=0rArrx=0#
#x-4=0rArrx=4#
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Answer 2

To solve the equation 3x^2 = 12x, you first want to rewrite it as a quadratic equation set to zero. So subtract 12x from both sides to get 3x^2 - 12x = 0. Next, factor out the common factor, which is 3x, to get 3x(x - 4) = 0. Now, apply the zero-product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, either 3x = 0 or x - 4 = 0. Solving these equations, you get x = 0 or x = 4. So the solutions are x = 0 and x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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