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How do you solve #3x^2 − 11x + 8 = 0#?

Answer 1

Nathan Axel

1 and #c/a = 8/3#

#y = 3x^2 - 11x + 8.# Since (a + b + c = 0), use shortcut. The 2 real roots are: (1) and #(c/a = 8/3)#

Reminder of Shorcut. - When a + b + c = 0 --> 2 real roots: 1 and #(c/a)#

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Answer 2

Eva Abramson

To solve the quadratic equation 3x^2 - 11x + 8 = 0, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Where: a = 3 b = -11 c = 8

Plugging in these values:

x = (11 ± √((-11)^2 - 4(3)(8))) / (2(3))

Simplify inside the square root:

x = (11 ± √(121 - 96)) / 6

x = (11 ± √25) / 6

x = (11 ± 5) / 6

So the solutions are:

x₁ = (11 + 5) / 6 = 16 / 6 = 8/3 x₂ = (11 - 5) / 6 = 6 / 6 = 1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.