How do you solve #-3x^2 –10 x + 8 = 0 #?

Answer 1

Solve y = -3x^2 - 10x + 8 = 0
Ans: #2/3# and -4

y = - 3x^2 - 10x + 8 = 0 (!) I use the new Transforming Method (Google, Yahoo Search) Transformed y' = x^2 - 10x - 24. = 0 (2) Roots have opposite signs. Factor pairs of (-24) --> (-2, 12). This sum is 10 = -b. Then, the 2 real roots of (2) are: -2 and 12. Back to equation (1). the 2 real roots are: #(-2)/-3 = 2/3# and #12/-3 = -4.#

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Answer 2

Eva Adamson

To solve the quadratic equation -3x^2 - 10x + 8 = 0, you can use the quadratic formula:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

In this equation, a = -3, b = -10, and c = 8. Plug these values into the formula and simplify to find the solutions for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.