Home > Algebra > Use Square Roots to Solve Quadratic Equations

How do you solve #3x^2+10=118#?

Answer 1

#x = +-6#

While this is a quadratic and we would usually make it equal to 0, this is a special case in that there is no term in x. Move the constants to the right side.

#3x^2 = 118-10#

#3x^2 = 108" "larrdiv# by 3

#x^2 = 36" "larr# find square root of both sides

#x = +-sqrt36#

#x = +-6#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Nathan Axel

To solve the equation 3x^2 + 10 = 118:

Subtract 10 from both sides to isolate the term with x^2: 3x^2 = 118 - 10 3x^2 = 108
Divide both sides by 3 to solve for x^2: x^2 = 108 / 3 x^2 = 36
Take the square root of both sides to solve for x: x = ±√36 x = ±6

So, the solutions for the equation are x = 6 and x = -6.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.