How do you solve #(3tan^2x1)(tan^2x3)=0# in the interval 0 to 2pi?
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To solve the equation (3tan^2x  1)(tan^2x  3) = 0 in the interval [0, 2π], you first set each factor equal to zero and solve for x:

For 3tan^2x  1 = 0: tan^2x = 1/3 tanx = ±√(1/3) x = arctan(±√(1/3))

For tan^2x  3 = 0: tan^2x = 3 tanx = ±√3 x = arctan(±√3)
After finding these solutions, you need to check which ones fall within the interval [0, 2π]. Ensure to consider all possible solutions within this interval.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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