How do you solve #3q+11=-1#?

Answer 1

#color(purple)("q= - 4")#

#color(coral)("Subtract 11 on both sides:")#
#3q+cancel11= -1# #color(white)(aa) -cancel11 -11#

On the left side, 11 cancels out, and on the right side, subtracting 11 from -1 yields -12:

#3q=-12#
#color(green)("Divide both sides 3 to get q by itself.")#
#(cancel"3"q)/cancel3=(-12)/3#
Now you are just left with #q# on the left side and -4 on the right side.
Thus, #color(red)"q = - 4"#
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Answer 2

To solve the equation 3q + 11 = -1, you need to isolate the variable q. First, subtract 11 from both sides of the equation to get 3q = -12. Then, divide both sides by 3 to solve for q. So, q = -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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