How do you solve #3p-1=5(p-1)-2(7-2p)#?

Answer 1

See answer in solution below.

In order to obtain individual terms, it's a good idea to start by distributing the numbers outside of both parentheses.

#3p - 1 = 5p - 5 -14 + 4p#

Next, we merge similar terms on both sides to obtain

#3p - 1 = 9p - 19#
Then we want to get the terms with #p# on one side and all the terms without #p# on the other side. It doesn't matter which one goes where but I prefer working with a positive coefficient in front of my variable so let's subtract #3p# from both sides and then add #19# to both sides to give us
#18 = 6p#
Then to get #p# alone we divide both sides by six which gives us
#3 = p#

And that's the definitive response.

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Answer 2

To solve the equation 3p - 1 = 5(p - 1) - 2(7 - 2p):

  1. Distribute any terms outside parentheses.
  2. Combine like terms.
  3. Solve for the variable.

Solution:

3p - 1 = 5(p - 1) - 2(7 - 2p) 3p - 1 = 5p - 5 - 14 + 4p 3p - 1 = 5p + 4p - 5 - 14 3p - 1 = 9p - 19

Subtract 3p from both sides:

-1 = 9p - 3p - 19 -1 = 6p - 19

Add 19 to both sides:

18 = 6p

Divide both sides by 6:

p = 3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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