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How do you solve #3n^2-14n=-16#?

Answer 1

2 and #8/3#

#y = 3n^2 - 14n + 16 = 0# Use the new Transforming Method (Google, Yahoo Search) Transformed equation #y' = n^2 - 14n +48 = 0# Factor pairs of (ac = 48) --> ...(4, 12)(6, 8). This sum is 14 = - b. Then, the 2 real roots of y' are: 6 and 8. Back to y, the 2 real roots are: #6/3 = 2# and #8/3#

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Answer 2

Eva Adamson

To solve the equation 3n^2 - 14n = -16, you can follow these steps:

Rewrite the equation in standard form, setting it equal to zero: 3n^2 - 14n + 16 = 0.
Factor the quadratic equation: (3n - 2)(n - 8) = 0.
Set each factor to zero and solve for n:
- 3n - 2 = 0
- n - 8 = 0
Solve for n in each equation:
- 3n = 2
- n = 8
Divide by 3 to isolate n:
- n = 2/3

Therefore, the solutions to the equation 3n^2 - 14n = -16 are n = 2/3 and n = 8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.