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How do you solve #(3k-7)/5=16#?

Answer 1

#color(blue)"k=29"#

#color(green)("Multiply both sides by 5 to remove the denominator,"#

#cancel5xx(3k-7)/cancel5=16xx5#

5 cancels out on the left side and you're left with #3k-7#. And, when 16 gets multiplied by 5, you get 80 on the right side:

#3k-7 = 80#

#color(magenta)("Add 7 to both sides:")#

#3k-cancel7=80# #color(white)(aa) +cancel7 color(white)(aa)+7#

The 7's cancel out, so you only have #3k# left. And when you add 80+7 on the right side, you obtain 87:

#3k=87#

#color(red)("Divide both sides by 3 to get k by itself:")#

#(cancel"3"k)/cancel3=87/3#

Now you are just left with #k# on the left side and 29 on the right side.

Thus, #color(blue)"k=29"#

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Answer 2

Isaiah Anthony

To solve (3k-7)/5=16, first multiply both sides by 5 to eliminate the denominator. Then, isolate the variable k by adding 7 to both sides. Finally, divide both sides by 3 to solve for k. The steps are as follows:

Multiply both sides by 5: (5 \times \frac{3k - 7}{5} = 16 \times 5)
Simplify: (3k - 7 = 80)
Add 7 to both sides: (3k = 87)
Divide both sides by 3: (k = \frac{87}{3})
Simplify: (k = 29)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.