How do you solve #38+5x >7 (x+4)#?
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First, let's switch the sides:
Hope this helps!
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To solve the inequality 38 + 5x > 7(x + 4):

Distribute 7 across (x + 4) on the right side: 38 + 5x > 7x + 28

Move variables to one side and constants to the other: 38  28 > 7x  5x

Simplify both sides: 10 > 2x

Divide both sides by 2 to solve for x: 10/2 > 2x/2

Simplify: 5 > x
So, the solution is x < 5.
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To solve the inequality ( 38 + 5x > 7(x + 4) ):
 Distribute 7 on the right side: ( 38 + 5x > 7x + 28 ).
 Subtract ( 7x ) from both sides: ( 38  2x > 28 ).
 Subtract 38 from both sides: ( 2x > 10 ).
 Divide both sides by 2 (note that dividing by a negative number reverses the inequality): ( x < 5 ).
So, the solution to the inequality is ( x < 5 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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