How do you solve #38.25> - 2q + 29.5#?

Answer 1

#q > -4.375#

#38.25 > -2q + 29.5#

Add #color(blue)(2q)# to both sides: #38.25 quadcolor(blue)(+quad2q) > -2q + 29.5 quadcolor(blue)(+quad2q)#

#38.25 + 2q > 29.5#

Subtract #color(blue)(38.25)# from both sides: #38.25 + 2q quadcolor(blue)(-quad38.25) > 29.5 quadcolor(blue)(-quad38.25)#

#2q > -8.75#

Divide both sides by #color(blue)2#: #(2q)/color(blue)2 > (-8.75)/color(blue)2#

Therefore, #q > -4.375#

I hope this is useful.

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Answer 2

Jace Anderson

To solve the inequality ( 38.25 > -2q + 29.5 ), follow these steps:

Subtract 29.5 from both sides of the inequality: ( 38.25 - 29.5 > -2q ).
Simplify the left side of the inequality: ( 8.75 > -2q ).
Divide both sides of the inequality by -2. Since dividing by a negative number flips the inequality sign, the inequality becomes ( -4.375 < q ).

Therefore, the solution to the inequality is ( q > -4.375 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #38.25&gt; - 2q + 29.5#?

How do you solve #38.25> - 2q + 29.5#?