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How do you solve #-31-4x=-5-5(1+5x)#?

Answer 1

Hazel Anglin

#x= 1#

First of all, multiply the # -5# by #(1+5x)# to get

# -5-25x #

Separate the #x#'s and the numbers by exchanging them.

#-31 - 4x = -5 - 5 - 25x#

You arrive at one side.

#25x-4x#

On the other:

# -10+31#

After adding, you get

#21x=21 #

Divide by #21# on both sides to get

#x=1 #

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Answer 2

Genesis Allen

To solve the equation -31-4x=-5-5(1+5x), first distribute the -5 to both terms inside the parentheses: -31-4x=-5-5-25x. Then, combine like terms: -31-4x=-10-25x. Next, add 25x to both sides to isolate the x terms: 21x-31=-10. Now, add 31 to both sides: 21x=21. Finally, divide both sides by 21 to solve for x: x=1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.