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How do you solve #3/(z+7)=2/(z-4)#?

Answer 1

Abigail Allen

#z=26#

#color(blue)(3/(z+7)=2/(z-4)#

Cross multiply #color(brown)(a/b=c/d,ad=bc#

#rarr3(z-4)=2(z+7)#

Use distributive property #color(brown)(a(b+c)=ab+ac#

#rarr3z-12=2z+14#

#rarr3z-2z=14+12#

#rarrz=14+12#

#color(green)(rArrz=26#

Check

#color(indigo)(3/(26+7)=2/(26-4)#

#color(indigo)(3/33=2/22#

#color(indigo)(1/11=1/11#

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Answer 2

Jameson Allen

To solve the equation 3/(z+7)=2/(z-4), you can start by cross-multiplying. Multiply 3 by (z-4) and 2 by (z+7). This gives you 3(z-4) = 2(z+7). Expand the equation by distributing the numbers: 3z - 12 = 2z + 14. Next, isolate the variable terms by subtracting 2z from both sides: z - 12 = 14. Finally, solve for z by adding 12 to both sides: z = 26. Therefore, the solution to the equation is z = 26.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.