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How do you solve #-3(x-5)<9#?

Answer 1

Avery Alexander

#x>2#

#-3(x-5) < 9#

#-3x + 15 < 9#

#-3x <-6#

Because the coefficient of #x# is negative, we change the #<# into a #>#, so divide both sides by #-3#

#x > 2#

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Answer 2

Eva Abramson

To solve the inequality -3(x - 5) < 9, first distribute the -3 to the terms inside the parentheses:

-3(x - 5) = -3x + 15

Now, the inequality becomes:

-3x + 15 < 9

Subtract 15 from both sides:

-3x < 9 - 15

-3x < -6

To isolate x, divide both sides by -3. Since we're dividing by a negative number, we need to reverse the inequality sign:

x > -6 / -3

x > 2

So, the solution to the inequality is x > 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #-3(x-5)&lt;9#?

How do you solve #-3(x-5)<9#?