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How do you solve # 3(x-5)^2 - 12 = 0#?

Answer 1

Eli Assouline

#x=5+2=7 and x= 5-2=3#

#3(x-5)^2=12# #=>(x-5)^2=12/3=4# #=>(x-5)=+-sqrt4=+-2# #x=5+2=7 and x= 5-2=3#

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Answer 2

Genesis Allen

To solve the equation 3(x-5)^2 - 12 = 0:

Add 12 to both sides to isolate the squared term: 3(x-5)^2 = 12
Divide both sides by 3 to isolate the squared term: (x-5)^2 = 4
Take the square root of both sides: x - 5 = ±√4
Solve for x: x - 5 = ±2 x = 5 ± 2
Simplify: x = 5 + 2 or x = 5 - 2 x = 7 or x = 3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.