How do you solve #-3( x + 3) > 7.5#?

Answer 1

#x < -5.5#

First, expand the term within parenthesis on the left side of the inquality:

#-3x - (3*3) > 7.5#
#-3x - 9 > 7.5#
Next, add #color(red)(9)# to each side of the equation to isolate the #x# term while keeping the inequality balanced:
#-3x - 9 + color(red)(9) > 7.5 + color(red)(9)#
#-3x - 0 > 16.5#
#-3x > 16.5#
Now, we can divide each side by #color(blue)(-3)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative term we must reverse the inequality:
#(-3x)/color(blue)(-3) color(red)(<) 16.5/color(blue)(-3)#
#(color(blue)(cancel(color(black)(-3)))x)/cancel(color(blue)(-3)) color(red)(<) 16.5/color(blue)(-3)#
#x < 16.5/color(blue)(-3)#
#x < -5.5#
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Answer 2

To solve the inequality -3(x + 3) > 7.5:

  1. Distribute -3 across the parentheses: -3x - 9 > 7.5

  2. Add 9 to both sides: -3x > 16.5

  3. Divide both sides by -3 (Note: Dividing by a negative number flips the inequality sign): x < -5.5

So, the solution to the inequality is x < -5.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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