How do you solve #3(x + 2) >x#?
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To solve 3(x + 2) > x, you would first distribute the 3 across the parentheses, then combine like terms, and finally isolate the variable x. The steps are as follows:
- Distribute 3 across the parentheses: 3x + 6 > x
- Subtract x from both sides to isolate the variable: 3x - x + 6 > 0
- Combine like terms: 2x + 6 > 0
- Subtract 6 from both sides: 2x > -6
- Divide both sides by 2 to solve for x: x > -3
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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