How do you solve #3(x2)+2(x+5)=5(x+1)+1#?
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Expand the terms in parenthesis:
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To solve the equation 3(x2)+2(x+5)=5(x+1)+1, follow these steps:

Distribute the terms inside the parentheses: 3x  6 + 2x + 10 = 5x + 5 + 1

Combine like terms on both sides of the equation: 5x + 2x + 3x  6 + 10 = 5x + 1 + 5 10x + 4 = 5x + 6

Move the variable terms to one side of the equation and the constant terms to the other side: 10x  5x = 6  4 5x = 2

Solve for x by dividing both sides by the coefficient of x: x = 2/5
So, the solution to the equation is x = 2/5.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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