How do you solve #3(x-1)=x#?

Answer 1

Genesis Allen

#x = 3/2#

This is simple. Just proceed step by step.

#color(white)(xxx)3(x - 1) = x#

#rArr 3x - 3 = x# [Use the distributive property to remove the #color(white)(xxxxxxxxxx)# parentheses]

#rArr 3x -x - 3 = x - x# [Subtract #x# from both sides]

#rArr 2x - 3 = 0#

#rArr 2x - 3 + 3 = 3# [Now Add #3# to both sides]

#rArr 2x = 3#

#rArr (2x)/2 = 3/2# [Now divide both sides by #2#]

#rArr x = 3/2#

Hence explained. Hope this helps.

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Answer 2

Julia Adams

To solve 3(x-1) = x, you would first distribute the 3 on the left side of the equation: 3 * x - 3 = x. Then, you would subtract x from both sides to isolate the x terms: 3x - x - 3 = 0. Simplify by combining like terms: 2x - 3 = 0. Finally, add 3 to both sides to isolate the x term: 2x = 3. Divide both sides by 2 to solve for x: x = 3/2 or 1.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.