# How do you solve #(3\times 3- ( 2+ 1) ) \div ( 5- 2)#?

BODMAS or PEMDAS rule states the order you have to complete operations in:

Usually we start with the parentheses within the parentheses. In other words, the smallest brackets.

Now, we have two brackets. What do we do?

[note: we do not do division now, as it is an operation outside the parentheses]

Now, we have two subtraction operations. Since both are withing brackets, and both are subtraction, they are on the same level on the BODMAS scale. We do them simultaneously:

We can remove the brackets, as there are no more operations within them:

Solve it:

Thus, solved.

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To solve (3 * 3 - (2 + 1)) ÷ (5 - 2):

First, perform the operations inside the parentheses: 3 * 3 = 9 2 + 1 = 3

Then, simplify the expression within the parentheses: 9 - 3 = 6

Now, perform the operation outside the parentheses: 5 - 2 = 3

Finally, divide the result of the expression within the parentheses by the result of the operation outside the parentheses: 6 ÷ 3 = 2

So, the solution is 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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