How do you solve #-3 sqrt(3x) = -5#?

Answer 1

#x=25/27#

Let's start by dividing both sides by #-3# to get
#sqrt(3x)=5/3#

To get rid of the radical, we can square both sides to get

#3x=25/9#
We can multiply both sides by #1/3# to isolate #x# to get
#x=25/27#

Hope this helps!

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Answer 2

#color(blue)(x=25/27#

#-3sqrt(3x) = -5#

Squaring both sides

#(-3sqrt(3x))^2 = (-5)^2#
#9 * 3x = 25#
#27x = 25#
#color(blue)(x=25/27#
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Answer 3

To solve the equation -3√(3x) = -5, we can follow these steps:

  1. Divide both sides of the equation by -3: √(3x) = -5/-3, which simplifies to √(3x) = 5/3.

  2. Square both sides of the equation to eliminate the square root: (√(3x))^2 = (5/3)^2. This gives us 3x = 25/9.

  3. Divide both sides of the equation by 3 to solve for x: x = (25/9) / 3, which simplifies to x = 25/27.

Therefore, the solution to the equation -3√(3x) = -5 is x = 25/27.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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