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How do you solve #3+ 7x = 73#?

Answer 1

Genesis Allen

#x=10#

#"isolate the term 7x by subtracting 3 from both sides"#

#cancel(3)cancel(-3)+7x=73-3#

#rArr7x=70#

#"divide both sides by "7#

#(cancel(7) x)/cancel(7)=70/7#

#rArrx=10#

#color(blue)"As a check"#

#3+(7xx10)=3+70=73larrcolor(blue)"True"#

#rArrx=10" is the solution"#

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Answer 2

Eli Assouline

#x# = 10

So, what you have to do firstly is subtract the #3# from the equation so you get: #7x = 70#

Then, you have to remember that #7x = 7 times x = 70# So #70/7 = 10#

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Answer 3

Eva Adamson

To solve the equation 3 + 7x = 73, first subtract 3 from both sides to isolate the term with x. This gives 7x = 70. Next, divide both sides by 7 to solve for x. This yields x = 10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.